SOLUTION: A LAWN WAS CUT TO A HEIGHT OF 2 IN. IT THEN GREW AT A RATE OF A 1/8IN. PER DAY. A) LINEAR MODEL OF L (LENGTH) AS A FUNCTION OF T (DAYS). B) WHEN WILL GRASS BE 3 1\2 IN.

Algebra ->  Rate-of-work-word-problems -> SOLUTION: A LAWN WAS CUT TO A HEIGHT OF 2 IN. IT THEN GREW AT A RATE OF A 1/8IN. PER DAY. A) LINEAR MODEL OF L (LENGTH) AS A FUNCTION OF T (DAYS). B) WHEN WILL GRASS BE 3 1\2 IN.      Log On


   



Question 283685: A LAWN WAS CUT TO A HEIGHT OF 2 IN. IT THEN GREW AT A RATE OF A 1/8IN. PER DAY.
A) LINEAR MODEL OF L (LENGTH) AS A FUNCTION OF T (DAYS).
B) WHEN WILL GRASS BE 3 1\2 IN.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
L=t/8+2
plug in 3.5 for L