SOLUTION: One pipe can fill a tank in 20 minutes. A second pipe can fill the tank in 30 minutes. If the tank is empty, how long would be required for the two pipes operating together to fill
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: One pipe can fill a tank in 20 minutes. A second pipe can fill the tank in 30 minutes. If the tank is empty, how long would be required for the two pipes operating together to fill
Log On
Question 248814: One pipe can fill a tank in 20 minutes. A second pipe can fill the tank in 30 minutes. If the tank is empty, how long would be required for the two pipes operating together to fill it?
I need the rate of work (R), the time of work (T) , and the work done (W)
the equation is RT = W.
It would help if I am provided a detailed explanation Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! One pipe can fill a tank in 20 minutes. A second pipe can fill the tank in 30 minutes. If the tank is empty, how long would be required for the two pipes operating together to fill it?
I need the rate of work (R), the time of work (T) , and the work done (W)
the equation is RT = W.
It would help if I am provided a detailed explanation
0 solutions
---------------------
1st Pipe DATA:
time = 20 min/job ; rate + 1/20 job/min
----------------------
2nd Pipe DATA;
time = 30 min/job ; rate = 1/30 job/min
----------------------
Together DATA:
time = x min/job ; rate = 1/x job/min
---------------------------------------
Equation:
rate + rate = together rate
1/20 + 1/30 = 1/x
---
Multiply thru by x to get:
work + work = job done
x/20 + x/30 = 1
Multiply thru by 60:
3x + 2x = 60
5x = 60
x = 12 min (time needed to complete the job when both pipes are operating)
=======================
Cheers,
Stan H.
(