SOLUTION: If three pipes are all opened, they can fill an empty swimming pool in 3 hours. The largest pipe alone takes 1/3 the time that the smallest pipe takes and half the time the other p

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: If three pipes are all opened, they can fill an empty swimming pool in 3 hours. The largest pipe alone takes 1/3 the time that the smallest pipe takes and half the time the other p      Log On

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 Click here to see ALL problems on Rate-of-work-word-problems Question 240503: If three pipes are all opened, they can fill an empty swimming pool in 3 hours. The largest pipe alone takes 1/3 the time that the smallest pipe takes and half the time the other pipe takes. How long would it take each pipe to fill the pool by itself?Answer by ankor@dixie-net.com(15649)   (Show Source): You can put this solution on YOUR website!If three pipes are all opened, they can fill an empty swimming pool in 3 hours. The largest pipe alone takes 1/3 the time that the smallest pipe takes and half the time the other pipe takes. How long would it take each pipe to fill the pool by itself? : To avoid those annoying fractions, do it like this : Let t = time required by the largest pipe alone then 3t = time of the smallest and 2t = time of the other pipe : Let the completed job = 1 (a full pool) : + + = 1 multiply by 6t, results 6(3) + 2(3) + 3(3) = 6t : 18 + 6 + 9 = 6t : 33 = 6t t = t - 5.5 hrs time of the largest pipe alone then 3(5.5) = 16.5 hrs time of the smallest pipe and 2(5.5) = 11 hrs time of the other pipe : : Check solution in the original equation, using a calc: + + = .545 + .182 + .273 = .9997 ~ 1