SOLUTION: A distillate flows into an empty 6 gallon drum at spout A and out at spout B.If the rate of flow through A is 2 gallon per hour.How many gallon per hour must flow out at spout B so

Question 218847: A distillate flows into an empty 6 gallon drum at spout A and out at spout B.If the rate of flow through A is 2 gallon per hour.How many gallon per hour must flow out at spout B so that the drum is full in exactly 96 hours.
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Rate of flow into the tank at spout A=2 gal/hr
Let x=rate of flow out at Spout B (gal/hr)

Net rate of flow into the tank=2-x
Now we know that net rate of flow into the tank times 96 hrs=6 gal
So, our equation to solve is:
(2-x)*96=6
192-96x=6 subtract 192 from each side
-96x=6-192
-96x=-186 divide each side by -96
x=1.9375 gal/hr----rate of flow out at Spout B (gal/hr)
CK
(2-1.9375)*96=6
0.0625*96=6
6=6
Hope this helps----ptaylor
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