# SOLUTION: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together t

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together t      Log On

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 Click here to see ALL problems on Rate-of-work-word-problems Question 183757: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? Answer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website!Steven mixes drinks at the rate of 4 drinks per min Sue mixes drinks at the rate of 2 drinks per min Jack mixes drinks at the rate of (4/3) drinks per min Together they mix drinks at the rate of 4+2+(4/3)=12/3 +6/3+4/3=22/3 drinks per min Let x=amount of time it takes all three working together to mix 20 drinks Then all three mixes drinks at the rate of 20/x drinks per min So, our equation to solve is: 22/3 = 20/x or 22x=60 x=2.73 min---------------amount of time it takes all three working together to mix 20 drinks CK 4*(2.73)+2*(2.73)+(4/3)(2.73)=20 10.9 +5.5+3.6=20 20=20 Hope this helps---ptaylor