SOLUTION: Here is my problem
If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time does it take all 3 of t
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Question 177029: Here is my problem
If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time does it take all 3 of them working together to mix 20 drinks/
Found 2 solutions by ankor@dixie-net.com, stanbon:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time does it take all 3 of them working together to mix 20 drinks/
;
let t = time required to mix 20 drinks working together:
:
let the completed job = 1; (the mixing of 20 drinks)
;
+ + = 1
mult eq by 30, results:
6t + 3t + 2t = 30
11t = 30
t =
t = 2.727 min or 2 + .727(60) = 2 min 43.6 sec
:
:
Check solution
+ + =
.5454 + .2727 + .1818 = .9999 ~ 1
;
SORRY ABOUT THE SCREW-UP HERE
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time does it take all 3 of them working together to mix 20 drinks/
---------------------------------
Steven rate = 20/5 = 4 drinks/min
Sue rate = 20/10 = 2 drinks/min
Jack rate = 20/15 = (1.333..)drinks/min
-----------------------------------------
Combined rate : (4+2+1.333) = (7.333..)drinks/min
-----------------
Time to mix 20 drinks:
Convert to 20 drinks/x min
(20/7.333..)drinks / (20/7.333..)min = 20drinks/2.72 min
================
Cheers,
Stan H.
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