# SOLUTION: An apprentice unpacked 12 dozen fragile lighting fixtures. He was to receive \$3 for each fixture that he unpacked safely and he agreed to pay \$25 for every one that he broke. If th

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: An apprentice unpacked 12 dozen fragile lighting fixtures. He was to receive \$3 for each fixture that he unpacked safely and he agreed to pay \$25 for every one that he broke. If th      Log On

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 Question 175340: An apprentice unpacked 12 dozen fragile lighting fixtures. He was to receive \$3 for each fixture that he unpacked safely and he agreed to pay \$25 for every one that he broke. If the amount due him for his work was \$236, how many did he break?Answer by nycsub_teacher(90)   (Show Source): You can put this solution on YOUR website!I got 2 equations here . Let x be the number of successful lightning fixtures Let y be the number of broken lightning fixtures. 12 dozen = 12 x 12 or 144 x + y = 144 3x - 25y = 236 We have two equations in two unknowns. Can you take it from here?