SOLUTION: An apprentice unpacked 12 dozen fragile lighting fixtures. He was to receive $3 for each fixture that he unpacked safely and he agreed to pay $25 for every one that he broke. If th

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: An apprentice unpacked 12 dozen fragile lighting fixtures. He was to receive $3 for each fixture that he unpacked safely and he agreed to pay $25 for every one that he broke. If th      Log On

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Question 175340: An apprentice unpacked 12 dozen fragile lighting fixtures. He was to receive $3 for each fixture that he unpacked safely and he agreed to pay $25 for every one that he broke. If the amount due him for his work was $236, how many did he break?
Answer by nycsub_teacher(90) About Me  (Show Source):
You can put this solution on YOUR website!
I got 2 equations here .
Let x be the number of successful lightning fixtures
Let y be the number of broken lightning fixtures.
12 dozen = 12 x 12 or 144
x + y = 144
3x - 25y = 236
We have two equations in two unknowns.
Can you take it from here?