# SOLUTION: Two printing presses, working together, can complete a job in 2 hours. If one press requires 6 hours to do the job alone, how many hours would the second press ned to complete the

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: Two printing presses, working together, can complete a job in 2 hours. If one press requires 6 hours to do the job alone, how many hours would the second press ned to complete the       Log On

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 Click here to see ALL problems on Rate-of-work-word-problems Question 164680: Two printing presses, working together, can complete a job in 2 hours. If one press requires 6 hours to do the job alone, how many hours would the second press ned to complete the job alone?Answer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website!Let x=amount of time required for the second press to complete the job alone Then the second press works at the rate of 1/x of the job per hour Together, the two presses work at the rate of 1/2 of the job per hour And the first press works at the rate of 1/6 of the job per hour So, our equation to solve is: 1/6+1/x=1/2 multiply each term by 6x x+6=3x subtract x from each side x-x+6=3x-x collect like terms 2x=6 divide both sides by 2 x=3 number of hours needed for the second press to complete the job CK 1/6+1/3=1/2 1/6+2/6=1/2 3/6=1/2 1/2=1/2 also (1/6)*2=1/3 (1/3)*2=2/3 2/3+1/3=1 (1 job, that is) 1=1 Hope this helps---ptaylor