# SOLUTION: Hi, I was hoping I could get some help... Sara takes 3 hours longer to paint a floor than it takes Katie. When they work together, it takes them 2 hours.How long would each take t

Algebra ->  Algebra  -> Rate-of-work-word-problems -> SOLUTION: Hi, I was hoping I could get some help... Sara takes 3 hours longer to paint a floor than it takes Katie. When they work together, it takes them 2 hours.How long would each take t      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Rate of work, PAINTING, Pool Filling Solvers Lessons Answers archive Quiz In Depth

 Question 136978: Hi, I was hoping I could get some help... Sara takes 3 hours longer to paint a floor than it takes Katie. When they work together, it takes them 2 hours.How long would each take to do the job alone? So far I have Sara=X+3 Kate=X (2/X+3 + 2/X = 1) all that multiplied by X(X+3) But I don't know what to do next, or even if that is right Thank you for the helpAnswer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!SORRY SORRY SORRY. i MISREAD THE PROBLEM AND USED SARA'S TIME AS 3 TIMES kATIE INSTEAD OF 3 HOURS LONGER. the formula for working together is: x*y/(x+y) time working together. Sara=k+3 Katie=k K(K+3)/(K+3+K)=2 (K^2+3K)/(2K+3)=2 K^2+3K=2(2K+3) K^2+3K=4K+6 K^2+3K-4K-6=0 K^2-K-6=0 (K-3)(K+2) K-3=0 K=3 HOURS FOR KATIE WORKING ALONE. 3+3=6 HOURS FOR SARA WORKING ALONE.