SOLUTION: Hi my question is : An orange is spherical. Suppose it grows so that its volume increases at an average rate of 4cm3 /day. a) Express the radius of the orange as a function o

Question 1199151: Hi my question is :
An orange is spherical. Suppose it grows so that its volume increases at an average rate of
4cm3 /day.
a) Express the radius of the orange as a function of time t in days.
b) Determine the radius of the orange six weeks after it begins growing.

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
An orange is spherical.
Suppose it grows so that it's volume increases at an average rate of 4cm3/day.
a) Express the radius of the orange as a function of time t in days.
Volume of a sphere: V =
let t = no. of growing days
= 4t
Get rid of the denominator, multiply both sides by 3
= 12t
=
=
r =
:
b) Determine the radius of the orange six weeks after it begins growing.
r =
r =
r =
r = 1.79 cm after 6 weeks
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