SOLUTION: Please help me solve this problem: There are two hoses filling up a pool. The two hoses have different capacities; using one hose, the job only takes 45 minutes, but using the oth

Question 1171603: Please help me solve this problem: There are two hoses filling up a pool. The two hoses have different capacities; using one hose, the job
only takes 45 minutes, but using the other hose would take 2 hours. How long would it take to fill up
the pool using both hoses?
I've tried: 1/x + 1/120 = 1/45, not sure what to do after this.
Thank you!
Answer by ikleyn(52887) (Show Source): You can put this solution on YOUR website!
.


One hose filling rate is   =   of the pool volume per hour (notice that 45 minutes =   of an hour).


Other hose filling rate is    of the pool volume per hour.


The combined rate of work is the sum   +  =  =   of the pool volume per hour.


Hence, the two hose, working together, will fill the pool in   of an hour, which is 32.72 of a minutes.    ANSWER

Solved.

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.
It is a standard and typical joint work problem.

There is a wide variety of similar solved joint-work problems with detailed explanations in this site. See the lessons
    - Using Fractions to solve word problems on joint work
    - Solving more complicated word problems on joint work
    - Selected joint-work word problems from the archive

Read them and get be trained in solving joint-work problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic
"Rate of work and joint work problems" of the section "Word problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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