SOLUTION: A ball is thrown from a height of 205 feet with an initial downward velocity of 11 ft/s. The balls height “h” (in feet) after “t” seconds is given by the following. H=205

Question 1145768: A ball is thrown from a height of 205 feet with an initial downward velocity of 11 ft/s. The balls height “h” (in feet) after “t” seconds is given by the following.
H=205-11t-16t squared
How long after the ball is thrown does it hit the ground?
Round to nearest hundredth
Answer by ikleyn(52866) (Show Source): You can put this solution on YOUR website!
.


This moment " t " is the root of the equation  H(t) = 0,  which is


    -16*t^2 - 11t + 205 = 0,


or, equivalently,


     16t^2 + 11t - 205 = 0.


Solve this quadratic equation using the quadratic formula.

Choose the positive root.  It will be your answer.

Having my instructions, you do the rest.

If you still have questions or problems with it, then let me know.

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