SOLUTION: Betty and Chris have a system of walking and jogging equal distances through a course in their neighbourhood. They walk at a rate of 6km/h and jog at a rate of 12km/h The total tim

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Question 1145633: Betty and Chris have a system of walking and jogging equal distances through a course in their neighbourhood. They walk at a rate of 6km/h and jog at a rate of 12km/h The total time required for them to walk and jog through the course is 2h How long is the course?
Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
.

Let  "d"  be the walking distance, in kilometers (the same as jogging distance (!) ).


Then the time walking is   hours, while the time jogging is   hours.


Total time is 2 hours


     +  = 2   hours.


It is your basic equation.  (Also called "time" equation)

At this point, the setup is completed.

To solve the equation, multiply both sides by 12


    2d + d = 2*12

    3d     = 24

     d     = 24/3 = 8 kilometers.


Distance walking = distance jogging = 8 kilometers.


The course is  8 + 8 = 16 kilometers long.    ANSWER

Solved.

----------------

Using  "time"  equation is the  STANDARD  method of solving such problems.

From my post,  learn on how to write,  how to use and how to solve a  "time"  equation.

To see many other similar solved problems,  look into the lessons
    - Had a car move faster it would arrive sooner
    - How far do you live from school?
    - Earthquake waves
    - Time equation: HOW TO use, HOW TO write and HOW TO solve it
in this site.


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