SOLUTION: Two equal sized vats, A and B containing 1000L of oil, are slowly being drained. Given that each Vat is being drained at a constant rate and that it takes 4 hours to drain Vat A co

Algebra.Com
Question 1098556: Two equal sized vats, A and B containing 1000L of oil, are slowly being drained. Given that each Vat is being drained at a constant rate and that it takes 4 hours to drain Vat A completely and 5 hours to drain Vat B completely, find the time at which the amount of oil in Vat B is four times the amount of oil in Vat A.
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
1000/4=250 L/h
1000/5=200 L/h
4(1000 - 250t)=1000 - 200t
4000 - 1000t=1000 - 200t
800t=3000
t=3.75 hours

RELATED QUESTIONS

a barrel contains 123 gallons of paint and is being drained at a constant rate of 12... (answered by Alan3354)
Container A has 200 L of water, and is being filled at a rate of 6 litters per minute.... (answered by lwsshak3)
Container A has 200 L of water, and is being filled at a rate of 6 liters per minute.... (answered by MathLover1,greenestamps)
a barrel contains 168 gallons of water and is being drained at a constant rate of 13... (answered by solver91311)
A barrel contains 178 gallons of gas and is being drained at a rate of 13 gallons per... (answered by stanbon)
a barrel contains 116 gallons of water and is being drained at a constant rate of 11... (answered by Alan3354)
a barrel contains 139 gallons of paint and is being drained at a constant rate of 8... (answered by josmiceli)
A barrel contains 106 gallons of paint and is being drained at a constant rate of 5... (answered by Alan3354)
A barrel contains 173 gallons of paint and is being drained at a constant rate of 6... (answered by colliefan)