SOLUTION: It takes worker A six days longer as it takes worker B to finish a certain job. Working together, they finish the job in 4days. How many days will it take each to finish the job

Question 1098146: It takes worker A six days longer as it takes worker B to finish a certain job. Working together, they finish the job in 4days. How many days will it take each to finish the job alone

Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!

Together they do the job in 4 days; so they do 1/4 of the job in 1 day.

Let x be the number of days worker A takes to do the job; then x+6 is the number of days worker B takes. Then 1/x is the fraction of the job worker A does in 1 day, and 1/(x+6) is the fraction worker B does in 1 day.

Now write the equation that says the amount they do together in 1 day is the sum of they each do alone in 1 day:

Then solve the equation....
Answer by ikleyn(52792)   (Show Source): You can put this solution on YOUR website!
.
There is a number of similar solved problems in the lesson
    - Using quadratic equations to solve word problems on joint work
in this site.

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Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this textbook under the topic
"Rate of work and joint work problems" of the section "Word problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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