SOLUTION: Stacey observed that it took w women 10 days to do j jobs. Then, she calculated how long it would take n more women to do 28 more jobs. What was her answer?

Question 1089976: Stacey observed that it took w women 10 days to do j jobs. Then, she calculated how long it would take n more women to do 28 more jobs. What was her answer?
Found 3 solutions by josmiceli, ankor@dixie-net.com, MathTherapy:
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
women - - days - - jobs
------------------------
w - - - - - - 10 - - - - - - - - - j
1 - - - - - - - 10w - - - - - - - - j
n + w - - - - - (10w)/( n+w ) - - j
n + w - - ( 10w ) / ( j*( n+w )) - - 1
n + w - - ( (10w)*( j+28 ) ) / ( j*( n+w )) - - j + 28
----------------------------------------------
( (10w)*( j+28 ) ) / ( j*( n+w )) days
get another opinion on this
I'm not 100% sure

Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Stacey observed that it took w women 10 days to do j jobs.
Find how many man-days for 1 job

Then, she calculated how long it would take n more women to do 28 more jobs. What was her answer?
* =
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Stacey observed that it took w women 10 days to do j jobs. Then, she calculated how long it would take n more women to do 28 more jobs. What was her answer?

kj = 10w ------- Cross-multiplying

------ Adding n MORE women, and 28 MORE jobs
---------- Cross-multiplying

T, or time =
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