SOLUTION: If a rock is thrown upwards with an initial velocity of 25 m/s from a cliff that is 5 m above the ground, where h denotes height and t denotes time. The equatin given for thi

Question 1085187: If a rock is thrown upwards with an initial velocity of 25 m/s from a cliff
that is 5 m above the ground, where h denotes height and t denotes time.
The equatin given for this relation is h = -6 t2 + 24t+5
a. How high is the rock after 3 seconds?
b. When will the rock reach a height of 29 m?
c. When will the rock reach the ground?
Found 2 solutions by jorel1380, ikleyn:
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
a. After 3 seconds: h=-6(9)+24(3)+5
Solve for h
b. 29=-6t�+24t+5
6t�-24t+24=0
Solve for t
c.When the rock hits the ground h=0, so:
6t�-24t-5=0
Solve for t
☺☺☺☺
Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
.
Your equation is totally wrong (for the Earth conditions).

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