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You have this system
9a + 8b = 770 (1)
5a + 6b = 490 (2)
Multiply eq(1) by 5 (both sides). Multiply eq(2) by 9 (both sides). You will get
45a + 40b = 3850 (1')
45a + 54b = 4410 (2')
Now subtract eq(1') from eq(2'). You will get
54b - 40b = 4410 - 3850, or
14b = 560 ---> b = = 40.
From this point please complete the solution on your own.
The method I used is called the "Elimination method".
On solving systems of two linear equations in two unknowns (Algebra-I curriculum) see the lesson
- Solution of the linear system of two equations in two unknowns by the Substitution method
- Solution of the linear system of two equations in two unknowns by the Elimination method
- Solution of the linear system of two equations in two unknowns using determinant
- Geometric interpretation of the linear system of two equations in two unknowns
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".