SOLUTION: two workers a and b together could finish the work in 8 days.they worked together for six days and a left the work.the remaining work was completed by b alone in 6 days.how many d

Algebra.Com
Question 1066248: two workers a and b together could finish the work in 8 days.they worked together for six days and a left the work.the remaining work was completed by b alone in 6 days.how many days would each take?

Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
If we have two workers, a & b, finishing a job in 8 days, then:
1/a + 1/b=1/8
They both work six days, so:
6/a + 6/b=6/8=3/4
This leaves 1/4 of the work to be done, which b does in 6 days, so:
6/b=1/4
b=24
1/8-1/24=1/a
3/24-1/24=1/a
2a=24
a=12
a alone would take 12 days to finish the job, b would take 24 days working alone. ☺☺☺☺

RELATED QUESTIONS

two workers a and b together could finish the work in 8 days.they worked together for six (answered by josgarithmetic)
Two workers A and B together could finish a work in 8 days. They worked together for 6... (answered by josgarithmetic,ikleyn)
Two workers and B together could finish a work in 8 days. They worked together for 6 days (answered by KMST)
Tow workers A and B together could finish a work in 8 days. They worked together for 6... (answered by ikleyn)
S and T can finish a work in 50 days. They worked together for 20 days and then left.... (answered by josgarithmetic)
Worker A can do a piece of work in 20 days. Workers A and B in 15 days. They work... (answered by richwmiller)
Person A can do a piece of work in 10 days. After he has worked for 2 days, B comes and... (answered by scott8148)
A can do a work in 32 days and B in 40 days. they work together for 10 days and then B... (answered by edjones)
A can do a work in 32 days and B in 40 days. they work together for 10 days and then B... (answered by mananth)