SOLUTION: If Janet can paint a wall in 10 hours but working with Linda, both of them can paint the fence in 4 hours. How long would it have taken Janet to paint the fence alone?
Algebra.Com
Question 1064332: If Janet can paint a wall in 10 hours but working with Linda, both of them can paint the fence in 4 hours. How long would it have taken Janet to paint the fence alone?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The time for Linda to paint the wall working alone is y:
SOLVE FOR y.
Your normal fractions skills.
LCD or simplest denominator is 10y.
Multiply left and right by 10y.
.
.
RELATED QUESTIONS
Lucy can paint a wall in 5 hours and working with Pedro the two of them can paint the... (answered by ikleyn)
Janet can paint a kitchen in 3 hours and Charles can paint the same kitchen in 5 hours .... (answered by Alan3354)
Bob can paint a fence in 5 hours, and working with Jen, the two of them painted the fence (answered by ikleyn)
Bob and Sarah need to paint a fence. Bob can paint a fence in 4 hours and Sarah can paint (answered by josgarithmetic,addingup,greenestamps)
ryan can paint a fence in ten hours. asanji can paint the same fence in eight hours. if... (answered by nerdybill)
It takes Dave 20 hours to paint a fence. When he works with Mike, they can paint the same (answered by Alan3354,jim_thompson5910)
Painters A and B can paint a wall in 10 hours when working at the sametime. Painter B... (answered by ewatrrr)
Painters A and B can paint a wall in 10 hours when working at the same time. Painter B... (answered by jorel1380)
If Sara can paint a house in 4 hours, and John can paint the same house in 6 hours, how... (answered by AnlytcPhil)