.
A AND B WORKING TOGETHER TAKE 8 AND 18 LESS DAYS THAN A ALONE AND B ALONE RESPECTIVELY TO DO A WORK.
THE NUMBER OF DAYS TAKEN BY A AND B WORKING TOGETHER TO DO THE WORK IS?
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Let x = THE NUMBER OF DAYS TAKEN BY A AND B WORKING TOGETHER TO DO THE WORK.
The the number of days for A to do the job working alone is (x+8), and
the number of days for B to do the job working alone is (x+18).
Then the standard equation for joint work is
= .
To solve it, multiply everything by x*(x+8)*(x+18). You will get
x*(x+18) + x*(x+8) = (x+8)*(x+18).
Simplify:
= , or
= 144.
Hence, x = = 12.
Answer. 12 days.
A wide variety of similar joint-work problems were solved with detailed explanations in the lessons
- Using Fractions to solve word problems on joint work,
- Solving more complicated word problems on joint work,
- Selected joint-work word problems from the archive
in this site.
Read them and become an expert in solving joint-work problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Rate of work and joint work problems" of the section "Word problems".
As a concluding remark, ignore writing by the other tutor, named "josgarithmetic".
The way he proposes is the way to nowhere.