SOLUTION: Prove that the roots of quadratic equation i.e ax2+bx+c=0 numerically equals but opposite in sign to the roots of ax2-bx+c

Algebra.Com
Question 1049893: Prove that the roots of quadratic equation i.e ax2+bx+c=0 numerically equals but opposite in sign to the roots of ax2-bx+c
Answer by advanced_Learner(501)   (Show Source): You can put this solution on YOUR website!
=
=
=

=+
=+





=

=
=

=+
=+






hence proved

RELATED QUESTIONS

One of the roots of the quadratic equation ax2+bx+c=0 is twice the other.Show (answered by richard1234)
Al-Khwarizmi solved all quadratic equations by reducing them to one of six standard... (answered by CPhill)
Find a quadratic function in the form of y = ax2 + bx + c that would have the given... (answered by tutorcecilia)
Find the condition that one of the roots of ax2 + bx + c may be (i) negative of the... (answered by ikleyn)
ax2 + bx + c = 0 what is the value of the discriminat to the graph of... (answered by stanbon)
Using the quadratic formula to solve for the roots. Given {{{3x^2+3x-2=0}}} I think... (answered by math_tutor2020,josgarithmetic,Solver92311)
• If you are looking at a graph of a quadratic equation y = ax2 + bx + c, how do you... (answered by stanbon)
If you are looking at a graph of a quadratic equation y = ax2 + bx + c, how do you... (answered by stanbon)
Developing and Analyzing the Quadratic Formula This formula, which is called the... (answered by stanbon)