SOLUTION: A and B can do a work in 12 days,B and C in 16 days. A started work and afte 7 days he stopd work and B started the work,after 5days B stopd work and remaining work was completed b
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Question 1039403: A and B can do a work in 12 days,B and C in 16 days. A started work and afte 7 days he stopd work and B started the work,after 5days B stopd work and remaining work was completed by C in 13days. In how many days A ,B,C alone can finish the work.
Answer by josgarithmetic(39628) (Show Source): You can put this solution on YOUR website!
a, b, c, the times in days for A, B, and C to do "one whole work". Use the work rates as in unit of .
A sequence of workers has done one whole job.
Goal is to solve for a, b, and c.
Use the first two equations to solve each in terms of b.
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Substitute these into the Finished In Thirteen Days equation.
Simplify.
, and simplest denominator IS 2*2*2*2*3*b;
------------Seems strange, maybe correct, but needs to be rechecked ... Maybe a mistake was made. If you can understand the process up to here, your work MIGHT be better and without any mistake I made. You could then continue to go back to the first two equations to solve for a and c.
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