Questions on Word Problems: Rate of work, PAINTING, Pool Filling answered by real tutors!

Algebra ->  Algebra -> Questions on Word Problems: Rate of work, PAINTING, Pool Filling answered by real tutors!     (Log On)
Ad: Algebra Solved!™: algebra software that solves YOUR algebra homework problems with step-by-step help!



Question 150823: A painter can do a given job in 6 hours. Her helper can do the same job in 10 hours. The painter begins the work and after two hours is joined by the helper. In how many hours will they complete the job?: A painter can do a given job in 6 hours. Her helper can do the same job in 10 hours. The painter begins the work and after two hours is joined by the helper. In how many hours will they complete the job?
Answer by mangopeeler07(442) About Me  (Show Source):
You can put this solution on YOUR website!
A painter can do a given job in 6 hours. Her helper can do the same job in 10 hours. The painter begins the work and after two hours is joined by the helper. In how many hours will they complete the job?

After 2 hours, the painter has done 2/6 or 1/3 of the work, so how much time will it take to do the other 2/3 of the job?

1/6+1/10=x
x=16/60-------------------rate of work together

16/60y=2/3

y=2.5

It will take them 2.5 hours to finish the job.