Tutors Answer Your Questions about Radicals (FREE)
Question 36464: Please help me solve this of x:
x^2=-5x-3 -------the +- means there is a + sign with a - under it
A)x=5+-sqrt13/2
B)x=5+-sqrt13
C)x=-5+-sqrt13/2
D)x=-5+-sqrt13
Please show me how you worked this out...thanks
Click here to see answer by Earlsdon(4900)  |
Question 36576: 3) For the equation x - 2 sqrt x = 0, perform the following:
a) Solve for all values of x that satisfies the equation.
Answer:
Show work in this space.
b) Graph the functions y = x and y = 2 sqrt x on the same graph (by plotting points if necessary). Show the points of intersection of these two graphs.
Graph:
Points of intersection:
Click here to see answer by rapaljer(3620)  |
Question 36758: Hi,
I need to simplify this and show my work, and I have not had this in a while. I have my answer, but am not sure if it is correct! Thank you kindly!
3 Radical Sign 32 (NOTE; THE RADICAL SIGN IS AROUND THE 32 I HOPE I WROTE THIS CORRECTLY)
Click here to see answer by longjonsilver(2297)  |
Question 36821: Please help.
4) A right triangle is a triangle with one angle measuring 90°. In a right triangle, the sides are related by Pythagorean Theorem, , where c is the hypotenuse (the side opposite the 90° angle). Find the hypotenuse when the other 2 sides’ measurements are 6 feet and 8 feet.
Answer:
Show work in this space .
Click here to see answer by stanbon(26273)  |
Question 36851This question is from textbook
: I am trying to remember how to do radical algebraic expressions and if you could just give me a sample that would be great an example problem is
150 over (square root sign) 300 and you have to simplify it.
PLEASE HELPThis question is from textbook
Click here to see answer by checkley71(8405)  |
Question 36958: Really need help.
4) A right triangle is a triangle with one angle measuring 90°. In a right triangle, the sides are related by Pythagorean Theorem,c^2= a^2 + b^2 , where c is the hypotenuse (the side opposite the 90° angle). Find the hypotenuse when the other 2 sides’ measurements are 6 feet and 8 feet.
Answer:
Show work in this space .
Click here to see answer by checkley71(8405)  |
Question 37095: Please please help me. I tried on my own but I don't know if I did it right and i don't want to look stupid. My professor has already been more than patient with me.
solve the following equations:
#1
A.
square root x-2=1
(show work)
****heres what I have*****
(sqrt x-2)^2=(1)^2
x-2=1
x=3
B.
sqrtx^3=27
show work
********heres what I have******
(sqrtx^3)^2=(27)^2
x^3=729
C.
3sqrtx^2=9
I really tried here but couldn't figure it out.
I appreciate your time.
Click here to see answer by checkley71(8405)  |
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