SOLUTION: can you help me simplify this radical expression?
the problem is cube root of 16x^4y, minus 3x times the cube root of 2xy, plus 5 times the cube root of -2xy^4
so far i have go
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Question 988089: can you help me simplify this radical expression?
the problem is cube root of 16x^4y, minus 3x times the cube root of 2xy, plus 5 times the cube root of -2xy^4
so far i have gotten 2 times the cube root of 2, times the cube root of x^4y, minus 3x times the cube root of 2 times the cube root of xy, plus 5 times times the negative cube root of 2 times the cube root of xy^4
Found 2 solutions by Boreal, solver91311:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
I am going to assume that 16x^4y is 16*x^4 *y.
Cube root of 16 is 2*2 ^1/3 (cube root of [8*2]
Term 1: 2*2^1/3 {x^4/3*y*1/3}
Term 2: -3*2^1/3 *x^(1/3)*y^(1/3)
Term 3: +5 *-2^1/3*x^1/3*y^4/3
;
common terms
2^1/3. That is multiplied by (2-3-5)
x^1/3. that is multiplied by (x)
y^1/3. That is multiplied by (y)
;
in front: 2^(1/3)*x^(1/3)*y^(1/3)* {2x-3-5y}
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\sqrt[3]{2xy})
\sqrt[3]{2xy})
Note the sign change in the second step because 
John
My calculator said it, I believe it, that settles it
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