SOLUTION: (24x^3y^4)^1/2 + (54xy^2)^1/2 =
Assuming x and y are positive real numbers
Algebra.Com
Question 979808: (24x^3y^4)^1/2 + (54xy^2)^1/2 =
Assuming x and y are positive real numbers
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
2 sqrt (6) x^(3/2)y^2 + 3 sqrt (6) x^(1/2) y. One takes the square root of each part, the number and each variable. sqrt (24)=sqrt(4)*sqrt (6); sqrt (54)=sqrt (9)*sqrt(6) or 3sqrt(6)
Factor out x^(1/2)y [sqrt(6)]
x^(1/2) y sqrt(6) {2 xy+3}
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