SOLUTION: Please help solve this equation {{{ sqrt(2x+5)-sqrt(x-2)=3}}} I know you should isolate the radical so you add sqrt(x-2) to 3 it becomes: {{{Sqrt(2x+5)=3+sqrt(x-2)}}} and you th

Question 964193: Please help solve this equation
I know you should isolate the radical so you add sqrt(x-2) to 3 it becomes:
and you then get rid of the radical so you have to square both side and then it cancles the radical. Now it's 2x+5=3+sqrt(x-2)^2 and then it's: 2x+5=3+sqrt(x-2)*3+sqrt(x-2) which equals: 2x+5=9+3sqrt(x-2)+3sqrt(x-2)+sqrt(x-2)^2 which cancels out and is just x-2.now we just combine like terms: 2x+5=7+6sqrt(x-2)+x now subtract 7 and x to 2x+5 and you get: x-2=6sqrt(x-2) and that's where I'm stuck I know you have to divide by 6 for both sides to isolate the radical and then square again but then what?I know the answer is x=2 and x=38 but how do you get it?
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!

Square BOTH sides.

Isolate the resulting radical.

Square both sides again.

, which does not seem factorable.

1904=16*119

(Possible mistake in this work)
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