if f(x)= 2x-3, then compute f(f(f(f(f(f(3)))))) f(3) = 2(3) - 3 = 3 so that means f(f(3)) = f(3) = 3 and f(f(f(3))) = f(3) = 3 and f(f(f(f(3)))) = f(3) = 3 ... and you can reason from there that you'll always get 3. So the answer is 3. Edwin