SOLUTION: Write a quadratic equation whose roots have a sum of 16 and a product of -80
Algebra.Com
Question 930152: Write a quadratic equation whose roots have a sum of 16 and a product of -80
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x + y = 16
y = 16 - x
---
xy = -80
x(16 - x) = -80
16x - xx = -80
xx - 16x - 80 = 0
---
the above quadratic equation is in standard form, with a=1, b=-16 and c=-80
---
to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 -16 -80
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
---
the quadratic has two real roots at:
---
x = 20
x = -4
---
answer:
xx - 16x - 80 = 0
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
RELATED QUESTIONS
Make a quadratic equation whose roots have a sum of 4 and a product of 3 and another... (answered by edjones)
Determine the quadratic equation whose roots have a sum of 12 and the roots difference is (answered by richwmiller,Alan3354,MathTherapy)
Write two equations whose roots have a sum of -2/3 and a product of... (answered by checkley71)
Write a quadratic equation such that the sum of its roots is 6 and the product of its... (answered by ankor@dixie-net.com)
Write a quadratic equation such that the sum of its roots is 6 and the product of its... (answered by richard1234,stanbon)
Write a quadratic equation such that the sum of its roots is 1212 and the product of its... (answered by ikleyn)
write the quadratic equation with a lead coefficient of 1 whose roots are 3 and... (answered by robertb)
construct a quadratic equation, if the sum and the product of the roots are 3 and -2... (answered by ikleyn)
Write the quadratic equation with a lead coefficient of 1 whose roots are -1/2 and... (answered by stanbon)