SOLUTION: Please help. (sqrt(n)+sqrt(n-1))(sqrt(n)-sqrt(n-1))=1 for n>=1 a.provide two numerical examples illustrating its validity. b.show the statement is true in general. c.what is th

Algebra.Com
Question 914968: Please help.
(sqrt(n)+sqrt(n-1))(sqrt(n)-sqrt(n-1))=1 for n>=1
a.provide two numerical examples illustrating its validity.
b.show the statement is true in general.
c.what is the difference between using numerical values to show that something is true and showing in general that something is true?

Answer by richard1234(7193)   (Show Source): You can put this solution on YOUR website!
a. n = 1 -->
n = 10 --> (you can easily check this)

b. Difference of squares or FOIL:


c. Showing the statement holds in general is a much stronger proof - checking a few cases usually does not constitute a valid proof. In fact, checking a few cases is widely considered invalid unless you can show that you checked all possible cases, or all possible cases reduce to ones you've already checked.

For example, to show that n^6 leaves a remainder of 0 or 1 when divided by 7, you only need to check n = 0,1,2,...,6 (do you see why?). However this is true by Fermat's little theorem.

RELATED QUESTIONS

Consider {{{ ( sqrt(n) + sqrt(n-1)) ( sqrt(n) - sqrt(n-1)) }}} =1 for n >or= 1... (answered by Edwin McCravy)
Consider {{{ (sqrt( n ) + sqrt( n-1 ) ( sqrt( n )- sqrt( n-1 ) }}} =1 for n=or> 1... (answered by josgarithmetic)
Trying to help my friend with his algebra, and I'm stumped as to what they're going for... (answered by jim_thompson5910)
sqrt (n) =... (answered by jim_thompson5910)
Show that n <= 1 +sqrt(2)+sqrt(3)+...+sqrt(n) <=... (answered by ikleyn)
Show that 1/sqrt 1 + 1/sqrt 2 + 1/sqrt 3...+ 1/sqrt n < 2*sqrt n for all positive... (answered by venugopalramana)
show that for every positive integers n sqrt (n-1)+(n+1) is... (answered by Edwin McCravy)
Proof by induction. Imagine that we are going to prove by induction that: (1/sqrt(1))... (answered by ikleyn)
(1/sqrt(1)) + (1/sqrt(2)) + (1/sqrt(3)) + ... + (1/sqrt(n)) >= sqrt(n), for all n E Z^+ (answered by ikleyn)