SOLUTION: {cuberoot(128x^5)} I took the cube root and factored the 128 to get 2*64x^5 a 4 is pulled out and 2 is left in the cubed root. Im not sure what to do about the x^5 in the cube

Question 887296: {cuberoot(128x^5)}
I took the cube root and factored the 128 to get 2*64x^5
a 4 is pulled out and 2 is left in the cubed root.
Im not sure what to do about the x^5 in the cubed root.
I think you pull out x^5 and get a finished product of:
(4x^5){cube root(2)}
Would this be correct? Thanks for the help!
Found 2 solutions by lwsshak3, MathTherapy:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
{cuberoot(128x^5)}

Answer by MathTherapy(10551) (Show Source): You can put this solution on YOUR website!
{cuberoot(128x^5)}
I took the cube root and factored the 128 to get 2*64x^5
a 4 is pulled out and 2 is left in the cubed root.
Im not sure what to do about the x^5 in the cubed root.
I think you pull out x^5 and get a finished product of:
(4x^5){cube root(2)}
Would this be correct? Thanks for the help!

You need to break up the RADICAND into CUBES.
, so:
becomes:
------ Rearranging radicand
----- Taking out 4 & x
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