SOLUTION: Square root of 6 * square root of 5 * square root of 4 * square root of 3 * square root of 2 * square root of 1 = k square root of 5
What is the value of k?
Thnx
Algebra.Com
Question 880580: Square root of 6 * square root of 5 * square root of 4 * square root of 3 * square root of 2 * square root of 1 = k square root of 5
What is the value of k?
Thnx
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
Square root of 6 * square root of 5 * square root of 4 * square root of 3 * square root of 2 * square root of 1 = k square root of 5
we need the prime factors for each term
(3^1/2 * 2^1/2) * 5^1/2 * (2^1/2 * 2^1/2) * 3^1/2 * 2^1/2 * 1^1/2
combine like terms by adding their exponents and note 1^1/2 = 1
3 * 2^2 * 5^1/2 = 12 * 5^1/2
k = 12
RELATED QUESTIONS
1.square root of 20 + square root of 80
2. square root of 12 - 2 square root of 3
3.... (answered by checkley71)
square root of 3/5 * square root of... (answered by rfer)
(4 square root of 3 plus 9 square root of 5).(square root 3 plus 6 square root of... (answered by checkley77)
(3+square root of 5)squared=(3+square root 5)(3+square root 5)
(answered by tns_tutor5000)
Square root of -3
(answered by jim_thompson5910)
-3* square root of 2 over square root of... (answered by persian52)
simplify each square root:
1. square root of -25
2. square root of 1.44
3. square root (answered by JulietG)
2 square root of 5
---------------------
-4 + square root of... (answered by solver91311)
2 square root of 5 × 3 square root of... (answered by Fombitz)