SOLUTION: {{{160 = Pi r Sqrt(36 + r^2)}}} Solve for "r" What I got up to: 160/Pi r = Sqrt(36 + r^2) (160^2)/(Pi^2 r^2) = 36 + r^2 36= ((160^2)/(Pi^2 r^2))

SOLUTION: {{{160 = Pi r Sqrt(36 + r^2)}}} Solve for "r" What I got up to: 160/Pi r = Sqrt(36 + r^2) (160^2)/(Pi^2 r^2) = 36 + r^2 36= ((160^2)/(Pi^2 r^2)) - r^2

Question 843034:
Solve for "r"
What I got up to:
160/Pi r = Sqrt(36 + r^2)
(160^2)/(Pi^2 r^2) = 36 + r^2
36= ((160^2)/(Pi^2 r^2)) - r^2
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Isolate r and any expressions with it onto one side; usually the simplest.

----- this is in quadratic form, and you need to first solve for .

Let
Let

-
----which part way to the answer.

which you still want to try to simplify.
RELATED QUESTIONS
Solve for "r"... (answered by checkley71,edjones)

Solce C=2(pi)r for... (answered by Earlsdon)

S=2(pi)r�h, for... (answered by Alan3354)

Solve for P: S = (pi)(r)^2 +... (answered by macston)

Solve for l: S = (pi)(r)^2 +... (answered by MathLover1)

Given: {{{S=(2*PI*r*h)+(2*PI*r^2)}}}, solve for... (answered by Earlsdon)

solve for g: r=(pi)*(g(r))^2 (answered by MathLover1)

Solve for h, where {{{S=2*pi*r^2 + 2*pi*r*h}}}. If you could correct my improper working... (answered by god2012)

I'd like to solve the below equation for r(s). s^2/2 = s*sqrt(r^2-s^2/4) + r^2/2 *... (answered by AnlytcPhil)