SOLUTION: If P is power (in watts) and R is resistance (in ohms), then the voltage V necessary to run the circuit is V=√PR Find the voltage necessary to run a 40-watt amplifier with

Algebra.Com
Question 82583: If P is power (in watts) and R is resistance (in ohms), then the voltage V necessary to run the circuit is V=√PR
Find the voltage necessary to run a 40-watt amplifier with a resistance of 150 ohms.
Okay I set the problem up and did the work. Did I get it right?
V=√40*150
V=√77.45966
V=38.72983

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
V=√(40*150)
V = sqrt(6000)
V = 77.46
================
Cheers,
Stan H.

RELATED QUESTIONS

the voltage in a circuit is given by the equation V= square root of PR, where P is the... (answered by bucky)
the voltage in a circuit is given by the equation V = square root of PR, where P is the... (answered by ankor@dixie-net.com)
Optimization The power absorbed by a circuit is p(x) = ((V^2)x)/(R+x)^2 where R is the (answered by Fombitz)
The voltage, 𝑉, in volts, in a circuit is the square root of the product of the power, (answered by greenestamps)
If the voltage V in an electric circuit is held constant, the current I is inversely... (answered by TheInstructor)
Question: If the voltage, V, is an electric circuit is held constant, the current, I , is (answered by Alan3354)
Ohm's law states that V=IR for a simple circuit, where V is the total voltage, I is the... (answered by ikleyn)
find the current in a circuit if the power is 500 w(watts) and the resistance is 25 ohms. (answered by Alan3354)
If the voltage, V, in an electric circuit is held constant, the current, I, is inversely... (answered by DrBeeee)