SOLUTION: Please show me how to solve a square root. I don't understand. Thanks My homework problem was: (3square root of 3)(square root of 7) the choices were: A.) 6 square ro

Algebra ->  Radicals -> SOLUTION: Please show me how to solve a square root. I don't understand. Thanks My homework problem was: (3square root of 3)(square root of 7) the choices were: A.) 6 square ro      Log On


   

Question 81358: Please show me how to solve a square root. I don't understand. Thanks
My homework problem was:
(3square root of 3)(square root of 7)
the choices were:
A.) 6 square root of 1323 (I chose this one)
B.) 6 square root of 3087
c.) 6 square root of 441
D.) 6 square root of 1029
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
(3square root of 3)(square root of 7)
.
Am I reading your problem correctly? I interpret as:
.
3%2Asqrt%283%29%29%2A%28sqrt%287%29%29
.
If this is, in fact the problem, the answer can be obtained under one radical sign as:
.
3%2Asqrt%283%2A7%29
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and this simplifies to:
.
3%2Asqrt%2821%29
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But this is not even close to any of the four answers you listed. Are you sure you
stated the problem correctly? Or have you listed the four answers for some other
problem?
.
If you use a calculator and compute the value of the four given answers you get:
.
A. 6%2Asqrt%281323%29+=+6%2A36.37306696+=+218.2384018
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B 6%2Asqrt%283087%29+=+6%2A55.56077753+=+333.3646652
.
C. 6%2Asqrt%28441%29+=+6%2A21+=+126
.
D. 6%2Asqrt%281029%29+=+6%2A32.07802986+=+192.4681792
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The way I interpreted what you said you can work your problem as:
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3%2Asqrt%283%29%2Asqrt%287%29
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Using a calculator, you can determine that sqrt%283%29+=+1.732050808 and sqrt%287%29+=+2.645751311
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Substituting these values into your problem for the appropriate square roots results in:
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3%2A1.732050808%2A2.645751311
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And multiplying this out results in the value of your problem being:
.
13.74772708
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Note that if you use your calculator to find 3%2Asqrt%2821%29 you get the same answer.
.
Notice also that this is not very close to the values we got above for each of the four
answers that you listed..
.
Sorry that I can't help you much more than that. If you do find your discrepancy,
please re-post the problem with the correction ... either in the problem itself or in
the answer list.
.
Hope that in this exercise there is something that helps you to learn a little more about
working with square roots.