SOLUTION: i have attempted to solve can someone please check for me? sqrt(2x+2)-6=0 2x+2^2=(6^2) 2x+2=36 2x=34 x=17

SOLUTION: i have attempted to solve can someone please check for me? sqrt(2x+2)-6=0 2x+2^2=(6^2) 2x+2=36 2x=34 x=17

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Question 81243: i have attempted to solve can someone please check for me?
sqrt(2x+2)-6=0
2x+2^2=(6^2)
2x+2=36
2x=34
x=17
Answer by tutor_paul(519) (Show Source): You can put this solution on YOUR website!

Get the square root term alone on one side of the equation:

Square both sides:

Solve for x:

Great job, you got it right!
Good Luck,
tutor_paul@yahoo.com
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