SOLUTION: Oh boy! tough one for me : ( One fourth of a herd of camels was seen in the forest, twice the square root of that herd had gone to the mountain slopes and 3 times 5 camels remai

Question 80346: Oh boy! tough one for me : (
One fourth of a herd of camels was seen in the forest, twice the square root of that herd had gone to the mountain slopes and 3 times 5 camels remained on the riverbank. What is the numerical measure of the herd of camels? Ugg! Please help! Thank you
Found 2 solutions by checkley75, scott8148:
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
c/4+2sqrtc+3*5=c
c/4+sqrtc+15=c
c/4+15+2sqrtc=c
2sqrtc=c-c/4-15
2sqrtc=3c/4-15
2sqrtc=(3c-60)/4
sqrtc=(3c-60)/8
c=[(3c-60)/8]^2
c=(9c^2-360c+3600)/64
64c=9c^2-360c+3600
9c^2-360c-64c+3600=0
9c^2-424c+3600=0
using the quadratic equation we get:
c=(424+-sqrt[-424^2-4*9*3600])/2*9
c=(424+-sqrt[179,776-129,600])/18
c=(424+-sqrt50,176)/18
c=(424+-224)/18
c=(424+224)/18
c=648/18
c=36 size of the herd.
proof
36/4+2*sqrt36+15=36
9+2*6+15=36
9+12+15=36
36=36
this was not an easy one :) :)

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
let h equal number in herd, then multiply by 4 and subtract (h+60) to get

square both sides to get .. subtract 64h to get

using quadratic formula .. or

since no fractional camels, h=36
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