SOLUTION: I need to solve for w and find the solution set for the following: Sqrt (5w-1) = w-3. I multiplied both sides by sqrt (5w-1) and got (5w-1) = w-3(sqrt (5w-1).

Question 79106: I need to solve for w and find the solution set for the following: Sqrt (5w-1) = w-3. I multiplied both sides by sqrt (5w-1) and got (5w-1) = w-3(sqrt (5w-1).
Found 2 solutions by Earlsdon, ptaylor:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for w:
Square both sides.
Subtract 5w from both sides.
Add 1 to both sides.
Factor this quadratic equation.
Apply the zero products principle:
or so...
or
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
I need to solve for w and find the solution set for the following: Sqrt (5w-1) = w-3. I multiplied both sides by sqrt (5w-1) and got (5w-1) = w-3(sqrt (5w-1).

At least you gave it a shot but you don't want to multiply both sides by the although it is a legal operation. You want to square both sides, in other words:
or
subtract (5w-1) from both sides
collect like terms and rearrange

quadratic in standard form and it can be factored. The factors are:

and

When you are dealing with a quadratic and the A coefficient is 1, then the B coefficient will be the sum of the factors of the C coefficient, if the quadratic is factorable.

Hope this helps---ptaylor
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