SOLUTION: can some one check this for me please?
sqrt{{{y+2}}}=5
sqrt{{{y+2}}}=5
(sqrt{{{y+2}}})^2=52
y+2=25
y=23
Algebra.Com
Question 79038: can some one check this for me please?
sqrt=5
sqrt=5
(sqrt)^2=52
y+2=25
y=23
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You did this correctly. As always you can plug in y=23 into y to check the answer.
note: since we squared the square root we'll only be looking for the positive square root
Check:
Plug in y=23
works. So this verifies our answer
RELATED QUESTIONS
Please solve this equation for me: {{{ sqrt( y+2 )=y... (answered by ankor@dixie-net.com)
(2 sqrt y - 3 sqrt 2)( 4 sqrt y - 5 sqrt... (answered by CubeyThePenguin)
Please Please help.
sqrt y-25=5 y=?
9 3/2 write without exponents
3 sqrt -125
(answered by jim_thompson5910)
Solve: sqrt{y} = 5+sqrt{2}/2 Thank... (answered by Fombitz)
Please help me regarding this question.
Solve for x and y by subsitution method.
(answered by mananth)
a) 6+ sqrt( x-y) = x+y+ 3sqrt(2)
b) xy+ sqrt( x+y) = 5/4 + sqrt(3)
c) x+y sqrt(5) =... (answered by ikleyn)
can you please check my work for me please?
sqrt{{{12x^3/5}}}... (answered by Earlsdon)
{{{sqrt(4x^2)/sqrt(y^3)}}} (answered by Jc0110)
Solve For Y:... (answered by ikleyn)