SOLUTION: can you please check this for me? I have to solve and check. sqrt{{{4x+1}}}+3+0 sqrt{{{4x+1}}}=-3 sqrt{{{4x+1}}}^2=(-3)^2 4x+1=3 x=-3 check sqrt{{{4(-3)}}}+1+3=0 sqrt{{{3

Algebra ->  Algebra  -> Radicals -> SOLUTION: can you please check this for me? I have to solve and check. sqrt{{{4x+1}}}+3+0 sqrt{{{4x+1}}}=-3 sqrt{{{4x+1}}}^2=(-3)^2 4x+1=3 x=-3 check sqrt{{{4(-3)}}}+1+3=0 sqrt{{{3      Log On

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Question 78177: can you please check this for me? I have to solve and check.
sqrt4x%2B1+3+0
sqrt4x%2B1=-3
sqrt4x%2B1^2=(-3)^2
4x+1=3
x=-3
check
sqrt4%28-3%29+1+3=0
sqrt3+3=0
6=0
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(21667) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%284x%2B1%29%2B3=0 Start with the given expression
sqrt%284x%2B1%29=-3 Subtract 3 from both sides
Since this equation is never true, there are no solutions (you cannot take a square root and get a negative number). But for the sake of the problem lets see what happens...

%28sqrt%284x%2B1%29%29%5E2=%28-3%29%5E2 Square both sides. Both sides will be positive so we will have 1 answer
4x%2B1=9
4x=8 Subtract 1 from both sides
x=2 Divide both sides by 4


Check:
sqrt%284x%2B1%29%2B3=0
sqrt%284%282%29%2B1%29%2B3=0 Plug in x=2
sqrt%288%2B1%29%2B3=0
sqrt%289%29%2B3=0
3%2B3=0
6=0 This is not true. We should have -3%2B3=0. But since we cannot take a square root and get a negative number, we have no solution.

Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt4x%2B1+3=0
sqrt4x%2B1=-3
{sqrt4x%2B1^2=(-3)^2
4x+1=9
4x=8
x=2
check
sqrt4%282%29%2B1+3=0
sqrt9+3=0
6=0
Answer does not check out.
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Cheers,
Stan H.