SOLUTION: can you please check this for me? I have to solve and check.
sqrt{{{4x+1}}}+3+0
sqrt{{{4x+1}}}=-3
sqrt{{{4x+1}}}^2=(-3)^2
4x+1=3
x=-3
check
sqrt{{{4(-3)}}}+1+3=0
sqrt{{{3
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Question 78177: can you please check this for me? I have to solve and check.
sqrt+3+0
sqrt=-3
sqrt^2=(-3)^2
4x+1=3
x=-3
check
sqrt+1+3=0
sqrt+3=0
6=0
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression
Subtract 3 from both sides
Since this equation is never true, there are no solutions (you cannot take a square root and get a negative number). But for the sake of the problem lets see what happens...
Square both sides. Both sides will be positive so we will have 1 answer
Subtract 1 from both sides
Divide both sides by 4
Check:
Plug in x=2
This is not true. We should have . But since we cannot take a square root and get a negative number, we have no solution.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
sqrt+3=0
sqrt=-3
{sqrt^2=(-3)^2
4x+1=9
4x=8
x=2
check
sqrt+3=0
sqrt+3=0
6=0
Answer does not check out.
=========
Cheers,
Stan H.
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