SOLUTION: The expression 5^square root of 32xh^7xS^8 over 5^square root of h^-5xS^-9 equals Kxh^rxS^t where r, the exponent of h, is: and t, the exponent of s, is: and k, the l

Question 776783: The expression
5^square root of 32xh^7xS^8 over 5^square root of h^-5xS^-9 equals Kxh^rxS^t
where r, the exponent of h, is:
and t, the exponent of s, is:
and k, the leading coefficient is:<--- which I know is 2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
5^square root of 32xh^7xS^8 over 5^square root of h^-5xS^-9 equals Kxh^rxS^t
------
5th root of [32h^7s^8] = 2hs*5th root of (h^2*s^3)
========================================================
where r, the exponent of h, is: 2
and t, the exponent of s, is: 3
and k, the leading coefficient is:<--- which I know is 2
==================
Cheers,
Stan H.
==================

RELATED QUESTIONS
Evaluate the expression: -5 exponent -1/2 (over) 2 square root of 5 (answered by london maths tutor)

The expression \frac{\sqrt[3]{8 h^{-2} s^{-4}}} { \sqrt[3]{ h^{6} s^{4}}} equals... (answered by richard1234)

rationalize the denominator for the expression square root 5 + square root of 55 all over (answered by jim_thompson5910)

r=THE SQUARE ROOT OF 3V DIVIDED BY PIE H (answered by Alan3354)

Square root of y over the square root of y plus the square root of... (answered by Alan3354)

the square root of 8 over the square root of... (answered by rfer)

2 over the square root of 5???? as in a fraction of 2/ (square root)... (answered by stanbon)

Which is a irrational number the square root of 5, the square root, of 9, the square root (answered by jim_thompson5910)

Simplify the radical expression. Exponent 3 square root x to the power of... (answered by ikleyn)