SOLUTION: (2x-2)^2=10
How do you solve finding the square root?
Algebra.Com
Question 773616: (2x-2)^2=10
How do you solve finding the square root?
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
(2x-2)^2=10
(2x-2)=sqrt(10), or (2x-2)=-sqrt(10)
x=1+(1/2)sqrt(10) or x=1-(1/2)sqrt(10)
RELATED QUESTIONS
How do you solve 24 divided by the square root of 2 .
24\square root... (answered by Alan3354)
How do u solve the equation by finding square roots... (answered by scott8148)
How do you find the square root of 4y^2 over x? I tried finding the square root of 4y^2... (answered by algebrahouse.com)
Solve the equation by finding the square root of both sides: {{{2x^2 = 32}}}
(answered by drj)
How do you simplify the following:
1. 3rd order radical of 432x^8 (instead of square... (answered by stanbon)
hello. how do i solve this please?
square root of x^2+2x+1
thank... (answered by josgarithmetic)
How do you solve this problem?
(SQUARE ROOT... (answered by malakumar_kos@yahoo.com)
How do I solve (2x-5)^2-180=0 Using the square root... (answered by stanbon)
How do I solve: (square root -6) - (square root... (answered by stanbon)