SOLUTION: Can you help me solve for real roots?
2x^8+15x^4=27
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Question 766857: Can you help me solve for real roots?
2x^8+15x^4=27
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
u=x^4
2u^2+15u-27=0
2u^2+18u-3u-27=0
2u(u+9)-3(u+9)=0
(2u-3)(u+9)=0
but u+9 contributes no real roots
2u-3=0
u=3/2
x^4 = 3/2
x^2 = +- sqrt(3/2)
from which we use the principal root
thus
or
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