SOLUTION: State the degree of each polynomial equation. Find all of the real and imaginary roots of each equation, stating multiplicity when it is greater than one. x^3 - 4x^2 - 6x = 0

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Question 728317: State the degree of each polynomial equation. Find all of the real and imaginary roots of each equation, stating multiplicity when it is greater than one.
x^3 - 4x^2 - 6x = 0
I know that the degree is 3 because of the highest power shown. but i was thinking that i should use the quadratic equation to find the multiplicity. i was wrong according to the answer section...2 +/- sqrt 10 please, can you show the work so that i can understand this problem

Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
x³ - 4x² - 6x = 0

Factor x out of the left side:

x(x² - 4x - 6) = 0

We use the zero factor property:

x = 0;   x² - 4x - 6 = 0

         x = 
         x = 
         x =          
         x = 
         x = 
         x = 
         x = 
         x = 
         x = 2±√10

So there are three solutions:

0, 2+√10, 2-√10

All have multiplicity 1, because there are the same number of
different solutions as the degree, which is 3.
 
Edwin

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