SOLUTION: Finding the real solutions to the equation:
Please help me solve this: 5x^2/3-24x^1/3-5=0
I got to the second part of this answer which is 125...but I cant figure out the fra
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Question 705740: Finding the real solutions to the equation:
Please help me solve this: 5x^2/3-24x^1/3-5=0
I got to the second part of this answer which is 125...but I cant figure out the fraction part. The answer should look something like this: -number/number,125
Found 2 solutions by Alan3354, lynnlo:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Finding the real solutions to the equation:
Please help me solve this: 5x^2/3-24x^1/3-5=0
-------------------
Sub u for x^(1/3)
------
5u^2 - 24u - 5 = 0
(5u + 1)*(u - 5) = 0
u = 5
x^(1/3) = 5
x = 125
--------------
u = -1/5
x = -1/125
Answer by lynnlo(4176) (Show Source): You can put this solution on YOUR website!
5x^2/3-24x^1/3-5=0
5x^2/3-8x^1/1-5=0
5x^2/3-8x^1-5=0
5x^2-8x-5=0
x=12+square root219/5 or12-square root219/5
x~5.3597,,,,,,,,,,,,-0.5597
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