SOLUTION: QUESTION:√(x+2)+4=x
MY WORK:
√(x+2) = x-4
√(x+2)^2 = (x-4)^2
X + 2 = (x-4)(x-4)
X+ 2 = x^2 – 4x – 4x + 16
X + 2 = x^2 – 8x + 16
x = x^2 – 8x + 14
0 = x^
Algebra.Com
Question 693450: QUESTION:√(x+2)+4=x
MY WORK:
√(x+2) = x-4
√(x+2)^2 = (x-4)^2
X + 2 = (x-4)(x-4)
X+ 2 = x^2 – 4x – 4x + 16
X + 2 = x^2 – 8x + 16
x = x^2 – 8x + 14
0 = x^2 – 9x + 14
(x – 7)(x - 2)
X = -7, -2 ?
√(x+2) + 4 = x
√(-7+2) + 4 = -7
√-5 = -12
√(x+2) + 4 = x
√(-2+2) + 4 = -2
Neither answer is correct, what the heck! Please help!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
QUESTION:√(x+2)+4=x
MY WORK:
√(x+2) = x-4
√(x+2)^2 = (x-4)^2
X + 2 = (x-4)(x-4)
X+ 2 = x^2 – 4x – 4x + 16
X + 2 = x^2 – 8x + 16
x = x^2 – 8x + 14
0 = x^2 – 9x + 14
(x – 7)(x - 2)
-------------
(x – 7)(x - 2) = 0
***********************
All you got wrong was the signs.
x = 2, x = 7
==================================
X = -7, -2 ?
√(x+2) + 4 = x
√(-7+2) + 4 = -7
√-5 = -12
√(x+2) + 4 = x
√(-2+2) + 4 = -2
Neither answer is correct, what the heck! Please help!
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