SOLUTION: I'm having trouble solving the following equation: square root of (3x-2) + square root of (2x+2) + 1 = 0. My major problem is coming from the fact that I'm getting stuck on isoloa

Question 68462: I'm having trouble solving the following equation:
square root of (3x-2) + square root of (2x+2) + 1 = 0. My major problem is coming from the fact that I'm getting stuck on isoloating the radical, and I'm a little confused on where to place 1. Please help.
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
First thing that you want to do is get rid of the radicals by squaring both sides but before you do that you want to rearrange the terms on either side of the equal sign in a manner that simplifies that process. Sometimes you will need to square both sides more than once. Lets move the 1 to the right side of the equal sign by subtracting 1 from both sides:
Now lets square both sides:
Lets collect like terms:
Now we will subtract 5x from both sides
Next lets square both sides again
Simplifying some we get
Next lets clear parens
Subtract 1 and 25x^2 from and add 10x to both sides
Collecting like terms:
Multiply through by -1
---------quadratic in standard form
This quadratic can be factored:

and

ck
substitute 1 in the original equation:
equals
and this equals

(+or-1)+(+or-2)+1=0

verify that it also checks for x=17

Hope this helps---ptaylor

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