SOLUTION: Can you please help me with this: Solve the equation: 3x^2-8x=0 Here is what i have: -8+_ sqrt (64-4(3)(0))/2(3) -8 +- sqrt 64-0/6 -8 +- 8/6 then -8-8/6 would be x=-16/6

Question 684570: Can you please help me with this:
Solve the equation:
3x^2-8x=0
Here is what i have:
-8+_ sqrt (64-4(3)(0))/2(3)
-8 +- sqrt 64-0/6
-8 +- 8/6
then -8-8/6 would be x=-16/6
and -8+8/6 would be x= 0/6
so it would be x=-16/6 x=0/6
Is this remotely close? Thanks!
Found 2 solutions by Alan3354, ankor@dixie-net.com:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve the equation:
3x^2-8x=0
---------------
x*(3x-8) = 0
x = 0
========
3x-8 = 0
x = 8/3
------------
You can use the quadratic equation.
----

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=64 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 2.66666666666667, 0. Here's your graph:

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Can you please help me with this:
Solve the equation:
3x^2 - 8x = 0
You are making this much harder than it is, just factor out x, and you have
x(3x - 8) = 0
Two solutions
x = 0
and
3x = 8
x = 8/3
:
:
Check in the original equation
3(8/3)^2 - 8(8/3) = 0
3(64/9) - (64/3) = 0
cancel 3 into 9
(64/3) - 64/9) = 0
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